6×65=390, the average 15 amp. circuit can support 1500 watts. If you have other loads on the circuit do the math . Watts divided by voltage. In this case 390/120=3.25 amps, nothing to worry about.
bsbmo33 said on 31-10-2009
I had 6 recessed lights installed in my living room. I had the divided and 3 are on one one switch and 3 on another switch. I like that idea, because I don’t have to turn all of them on at one time. I hope this helps.
Dennis said on 31-10-2009
Watts Law P = E x I or Watts = Voltage X Amps So, 6 lights @ 65W ea = 390 Watts Then 390 = 120v X 3.2 Amps In others words, with all 6 fixtures on, this would equal about 3.2 Amps total draw. Most residential circuits are either 15 or 29 Amp circuits. Hope this helps.
John himself said on 31-10-2009
What is the present load on the circuit? Your 6 lights will add 3.25 amps load to the circuit.
6×65=390, the average 15 amp. circuit can support 1500 watts. If you have other loads on the circuit do the math . Watts divided by voltage. In this case 390/120=3.25 amps, nothing to worry about.
I had 6 recessed lights installed in my living room. I had the divided and 3 are on one one switch and 3 on another switch. I like that idea, because I don’t have to turn all of them on at one time. I hope this helps.
Watts Law P = E x I or Watts = Voltage X Amps So, 6 lights @ 65W ea = 390 Watts Then 390 = 120v X 3.2 Amps In others words, with all 6 fixtures on, this would equal about 3.2 Amps total draw. Most residential circuits are either 15 or 29 Amp circuits. Hope this helps.
What is the present load on the circuit? Your 6 lights will add 3.25 amps load to the circuit.