Comments on: How can I determine if a given circuit can accomidate 6 recessed lighting fixtures ? (1 fixture = 65 watts)?

By: hoboson

hoboson — Sat, 31 Oct 2009 11:11:52 +0000

6×65=390, the average 15 amp. circuit can support 1500 watts. If you have other loads on the circuit do the math . Watts divided by voltage. In this case 390/120=3.25 amps, nothing to worry about.

By: bsbmo33

bsbmo33 — Sat, 31 Oct 2009 11:11:52 +0000

I had 6 recessed lights installed in my living room. I had the divided and 3 are on one one switch and 3 on another switch. I like that idea, because I don’t have to turn all of them on at one time. I hope this helps.

By: Dennis

Dennis — Sat, 31 Oct 2009 11:11:52 +0000

Watts Law P = E x I or Watts = Voltage X Amps So, 6 lights @ 65W ea = 390 Watts Then 390 = 120v X 3.2 Amps In others words, with all 6 fixtures on, this would equal about 3.2 Amps total draw. Most residential circuits are either 15 or 29 Amp circuits. Hope this helps.

By: John himself

John himself — Sat, 31 Oct 2009 11:11:52 +0000

What is the present load on the circuit? Your 6 lights will add 3.25 amps load to the circuit.